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Unformatted text preview: through the bulb when it is operating on 120 V? current = 120/48 = 2.5 A 5. Which costs more, running a 1,200 W hair dryer for 3 min or leaving a 60 ‐ W lamp on overnight (1h)? hair dryer = 1.2 kW * (1/20) h = 24 kW.h lamp = .006 kW * 1 h = .006 kW.h so, the hair dryer costs more. Week 6 3 3 6. Solve the PROBLEM NUMBER 14 mentioned on page 287 of your text book. All of the electrical outlets in a room are connected in a single parallel circuit. The circuit is equipped with a 20-A fuse, and the voltage is 120 V. A. What is the maximum power that can be supplied by the outlets without blowing the fuse? 120 V * 20 A = 2400 W B. How many 1,200-W appliances can be plugged into the sockets without blowing the fuse? 2400 W/1200 W = 2 appliances...
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- Spring '09
- Trigonometry, Incandescent light bulb, Electrical resistance, hair dryer, Jeremy Doncouse