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Doncouse_Jeremy_Week6

# Doncouse_Jeremy_Week6 - through the bulb when it is...

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Running head: WEEK 6 1 1 Week 6 Assignment Jeremy Doncouse Mountain State University

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Week 6 2 2 Week 6 Assignment – Phys 101 Online Electricity 1. A lightning stroke lasts 0.05 s and involves a flow of 200 C. What is the current? I = Q/t = 4000 A 2. A calculator draws a current of 0.0003 A for 5 min. How much charge flows through it? .09 * 60 sec * 5 min = 27 C 3. A current of 15 A flows through an electric heater operating on 120 V. What is the heater’s resistance? Compute the power consumption of the electric heater in kW? How much energy does it use in 600 min (=10 hours)? ( Express the answers in both units: kWh and Joule ) R = 120/15 = 8 ohms W = 1.8 kW * 10 hrs = 0.18 kWh 1 kWh = 3.6*10 6 J 0.18 kWh = 6.48*10 5 J 4. The light bulb used in an overhead projector has a resistance of 48 Ohm. What is the current
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Unformatted text preview: through the bulb when it is operating on 120 V? current = 120/48 = 2.5 A 5. Which costs more, running a 1,200 W hair dryer for 3 min or leaving a 60 ‐ W lamp on overnight (1h)? hair dryer = 1.2 kW * (1/20) h = 24 kW.h lamp = .006 kW * 1 h = .006 kW.h so, the hair dryer costs more. Week 6 3 3 6. Solve the PROBLEM NUMBER 14 mentioned on page 287 of your text book. All of the electrical outlets in a room are connected in a single parallel circuit. The circuit is equipped with a 20-A fuse, and the voltage is 120 V. A. What is the maximum power that can be supplied by the outlets without blowing the fuse? 120 V * 20 A = 2400 W B. How many 1,200-W appliances can be plugged into the sockets without blowing the fuse? 2400 W/1200 W = 2 appliances...
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Doncouse_Jeremy_Week6 - through the bulb when it is...

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