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Unformatted text preview: at least 3.0? P ( X ≥ 3.0 ) = ≥ 4 76 2 3 Z P . . . = P ( Z ≥ 0.60 ) = 1 – Φ ( z = 0.60 ) = 1 0.7257 = 0.2743 . 27.43% . c) (4) What is the probability that a randomly selected student would have a GPA between 2.3 and 3.0? P ( 2.3 < X < 3.0 ) = < <4 76 2 3 Z 4 76 2 3 2 P . . . . . . = P ( – 1.15 < Z < 0.60 ) = Φ ( 0.60 ) – Φ ( – 1.15 ) = 0.7257 – ( 1 – 0.8749 ) = 0.7257 – 0.1251 = 0.6006 . 60.06% ....
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This note was uploaded on 11/28/2011 for the course STAT 400 taught by Professor Kim during the Spring '08 term at University of Illinois, Urbana Champaign.
 Spring '08
 Kim

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