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Unformatted text preview: Find the minimum GPA needed to be on the Honor List. Need x = ? such that P ( X > x ) = 0.04. Find z such that P ( Z > z ) = 0.04. Φ ( z ) = 1 – 0.04 = 0.96 . z = 1.75 . 75 1 45 64 2 . . . x =. x = 3.4275 . c) (4) What is the probability that a randomly selected student would have a GPA between 2.1 and 3.0? P ( 2.1 < X < 3.0 ) = < <45 64 2 3 Z 45 64 2 1 2 P . . . . . . = P ( – 1.20 < Z < 0.80 ) = Φ ( 0.80 ) – Φ ( – 1.20 ) = 0.7881 – ( 1 – 0.8849 ) = 0.7881 – 0.1151 = 0.6730 . 67.30% ....
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 Spring '08
 Kim
 Normal Distribution, Standard Deviation, 4%, Anytown College, 21.19%, 67.30%

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