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Unformatted text preview: Need x such that P( X > x ) = 0.10. Need z such that P( Z > z ) = 0.10. Φ ( z ) = 1 – 0.10 = 0.90. z = 1.28 . z x =σ μ 28 . 1 5 69 =x . x = 69 + 5 ⋅ 1.28 = 75.4 inches. A male must to be over 75.4 inches tall. c) (3) How "tall" must a male be to be among the shortest third of the population? Need x such that P( X < x ) = 0.3333. Need z such that P( Z < z ) = 0.3333. Φ ( z ) = 0.3333. z = – 0.43 . z x =σ μ 43 . 5 69=x . x = 69 + 5 ⋅ ( – 0.43 ) = 66.85 inches. A male must to be under 66.85 inches "tall." If P( X < x ) = 0.33, then x = 69 + 5 ⋅ ( – 0.44 ) = 66.8 inches....
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 Spring '08
 Kim
 Normal Distribution, Standard Deviation, inches, Inch

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