This preview shows page 1. Sign up to view the full content.
Unformatted text preview: P ( X 8 ) = P( X < 8.5 ) T P ( X < 8.5 ) = < 19 . 2 6 5 . 8 Z P = P ( Z < 1.14 ) = 0.8729 . ( Binomial distribution, n = 30, p = 0.20, P ( X 8 ) = 0.87135. ) 2. (5) A communication system for a company has 40 outside lines. If the number X of line requests at a given time follows a Poisson distribution with mean 36, compute the probability that an incoming call cannot find an open line. That is, find the probability that the number of lines needed, X, exceeds 40. (Use Normal approximation.) Need P(X > 40) = ? o = = 36. = = 6. t 0.5 correction: do not want 40, want 41. P(X > 40.5) = ? T P(X > 40.5) = P < 6 36 5 . 40 Z = P(Z > 0.75) = 1 (0.75) = 0.2266 . ( Poisson distribution, = 36, P(X > 40) = 0.2229. )...
View Full
Document
 Spring '08
 Kim

Click to edit the document details