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Unformatted text preview: MIT OpenCourseWare 5.80 Small-Molecule Spectroscopy and Dynamics Fall 2008 For information about citing these materials or our Terms of Use, visit: MASSACHUSETTS INSTITUTE OF TECHNOLOGY Chemistry 5.76 Spring 1977 Problem Set #4 1. The corners of a cube are numbered 1, 2, 3, 4 clockwise around the top face of the cube, and 5, 6, 7, 8 clockwise around the bottom face, corner 5 lying under corner 1, corner 6 under corner 2, and so on. A face center is denoted by the two numbers of the corners between which a face diagonal can be drawn which passes through that face center (for example, either 13 or 24 would denote the center of the top face). (a) The structures of several kinds of A B4 molecules are described as follows with the above numbering system. The A–atom is placed at the center of the cube, and the A— B bond distances are given by the cube dimensions. However, the B–atoms are not necessarily all equivalent, the actual equivalence being determined by the symmetry elements remaining in the A B4 structures. (i) A B4 (1, 2, 3, 4) (ii) A B4 (1, 3, 5, 7) (iii) A B4 (1, 3, 6, 8) (iv) A B4 (1, 5, 16, 18) (v) A B4 (13, 36, 68, 18) Give the point-group symbol for each A B4 structure (for example, C3v , D6h , and so on). (b) Classify the five molecules of Part (a) as to type of molecular rotator (linear, symmetrical top, and so on). (c) Which of the five molecules of Part (a) will give a pure-rotational spectrum in the far-infrared or mi­ crowave region? Which will give a pure-rotational Raman effect? 2. The harmonic oscillator (mass m) in two dimensions has a potential energy V expressed in polar coordinates r, θ, of the general form 2V = k1 r2 cos2 θ + k2 r2 sin2 θ, where k1 and k2 are force constants. For the special case o k1 = k2 = k, the oscillator has a single frequency v = (k/m)1/2 /2π, and its Schr¨ dinger equation has solutions of the form � −αr2 = Nv,� exp exp(i�θ)P(r) 2 � ψv,� where v, � are quantum numbers (v = 0, 1, 2, . . . , ∞; ±� = 0, 2, 4, . . . , v for v even, ±� = 1, 3, 5, . . . v for v odd); Nv,� is a normalization constant; α = 4π2 mv/h; P(r), a polynomial in r only, depends for its form on the values of v and � and is an even function for even v, odd for odd v. 5.76 Problem Set #4 Spring, 1977 page 2 (a) The energy levels of this two-dimensional oscillator are Ev = (v + 1)hv. What is the degeneracy of the v–th level? (b) Find Nv,� for v = 1, � = +1, for which P(r) = α1/2 r. (c) Show that any two ψ’s of the same v but different � are orthogonal. (d) Find the average value of the angular momentum pθ for any state v, �. (e) Find the average value of r−2 for the state v = 1, � = +1. Substitute the results of the above in the equation for the relationship between E and pθ in the plane rotor and find E for the state v = 1, � = +1. Explain the difference between this value of E and that given by the equation of Part (a). 3. The carbon suboxide molecule C3 O2 , is believed to be linear and symmetrical. (a) Classify the normal vibrations of C3 O2 according to the symmetry species of point group D∞h . (b) How many polarized lines should appear in the vibrational Raman spectrum? How many fundamental infrared bands should have P–, Q–, and R–branches? 4. Suppose that there are two possible structures for ethylene, planar D2h and nonplanar D2d . (a) Work out the infrared-active and the Raman-active vibrational species for each point group. (b) Work out the distribution of fundamental vibrational frequencies among the different species of the two structures and compare the results. What would you look for spectroscopically to decide between the two structures? (c) What kind of rotational fine structure would you expect in the vibrational infrared bands of the D2h model? What kind for the D2d model? 5. Make a complete analysis of the spectrum of BF3 given below and prove the symmetry of the molecule. (Chemical evidence gives a start.) B11 F3 480.4 cm−1 691.3 888.0 1445.9 1831.0 2903.2 B10 F3 482.0 cm−1 719.5 888.0 1497.0 1928.0 3008.2 Raman m — s — — — IR s s — vs w w Note that the 888 cm−1 band has the same value for both isotopic species. This is a critical point in clinching the symmetry. 5.76 Problem Set #4 6. Spring, 1977 page 3 (a) Let ψa ≡ ψv1 =1 (Q1 )ψv2 =0 (Q2 ) and ψb ≡ ψv1 =0 ψv2 =2 be the normalized harmonic-oscillator wave functions of a polyatomic molecule corresponding to excited vibrational states of unperturbed energies Ea and Eb . If these two states are in Fermi resonance, second-order non-degenerate theory can be applied. Assume � � � that the interaction energies Haa and Hbb are zero and that Hab arises from one or more anharmonic terms in the potential function. In a certain molecule, the levels ψa and ψb are observed to be in Fermi resonance, the transitions to the perturbed levels being observed at 1400 and 1500 cm−1 , whereas the level ψv1 =0 ψv2 =1 has an energy of 740 cm−1 above the zero level (see diagram). Deduce the unperturbed � Ea –value from the above data (Hab is to be evaluated from the data, not by integration). (b) The intensity of the Raman line for the transition from the ground state ψ0,0 to the unperturbed state ψa in the absence of Fermi resonance is proportional to the square of the matrix element � � �� � ∂α � � � � ψ0,0 � Q 1 � ψa ∂Q1 � where ∂α/∂Q1 is a non-zero constant. The corresponding matrix element � � �� � ∂α � � � � Q 2 � ψb ψ0,0 � ∂ Q2 � is zero because Δv2 = 2. Find the ratio of the intensities of the two Raman lines for the transitions from state |ψ00 � to the perturbed states |ψA � and |ψB �. ...
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This note was uploaded on 11/28/2011 for the course CHEM 5.74 taught by Professor Robertfield during the Spring '04 term at MIT.

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