PHYS_2014_Lecture_16

PHYS_2014_Lecture_16 - Fall 2010 Oklahoma State University...

Info iconThis preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Fall 2010 Oklahoma State University PHYS2014: Benton Lecture 16, Slide 1 The class will be divided into three groups based on their recitation TA. Each group will take the exam in a different room as shown in the table below. Based on your recitation section, please go directly to your designated room. Note that rooms for Mr. Patra’s and Mr. Stoian’s students have been switched. Mid-term Exam on 19 Oct. 2010 5:30 - 7:00 pm Recitation Section TA Exam Room 1, 2, 3, 19, 20, 21, 22, 23, 24 Ayon Patra PS-141 4, 5, 6, 7, 8, 9, 16, 17, 18, Ben Grossman PS-103 10, 11, 12, 13, 14, 15, 25, 26, 27, 28, 29, 30 Razvan Stoian PS-110 Fall 2010 Oklahoma State University PHYS2014: Benton Lecture 16, Slide 2 Regarding Exam 2 • Homework Set No. 6 will not be collected or graded, since there is no recitation on Friday, 10/15/2010. • Solutions to Homework Set No. 6 will be posted on Friday. • There will be a help session on Wednesday, 10/13/2010 at 5:30 in PS052. • Exam 2 will cover everything we’ve covered up through Homework Set No. 6. • Emphasis will be on material in Homework Sets Nos. 4, 5, and 6. • Orbital motion will be included on Exam 2 ; collisions will not be included on Exam 2 . • The exam will be of the same format and follow the same rules as Midterm Exam No. 1. Fall 2010 Oklahoma State University PHYS2014: Benton Lecture 16, Slide 3 Newton’s Cradle: An Elastic Collision Machine 1 2 1 2 p p K K = = 2 3 2 3 p p K K = = 3 4 3 4 p p K K = = 4 5 4 5 p p K K = = 1 5 1 5 1 5 2 2 1 5 1 1 2 2 p p Mv Mv K K Mv Mv = = = = Ball 1 is lifted to a height h i above the other balls, then released M M M M M h i M M 1 2 3 4 5 Fall 2010 Oklahoma State University PHYS2014: Benton Lecture 16, Slide 4 1 5 2 2 1 5 1 1 2 2 gi gf i f U K K U Mgh Mv Mv Mgh = = = = = = Ball 5 rises to height h f = h i , stops, then falls back in the opposite direction. M M M M M h i M M 1 2 3 4 5 h f Ideally, Newton’s Cradle should keep working forever, i.e is a perpetual motion machine. Obviously, this is not the case. Newton’s Cradle: An Elastic Collision Machine Fall 2010 Oklahoma State University PHYS2014: Benton Lecture 16, Slide 5 θ = 12 ο l = 15 cm a) With what velocity does the first ball collide with the second? b) What is the maximum vertical angle that the second ball’s string makes with respect to the vertical? A Newton’s Cradle consists of only two steel balls, each with mass of 20 g, a diameter of 1.7 cm, and each suspended from a 15 cm long string. The left ball is pulled so that its string makes a 12 ° angle with respect to the vertical and is then released. When the ball swings back to its original position, it collides elastically with the second ball. The second ball swings to the right before coming to a stop and then swinging back to the left. Fall 2010 Oklahoma State University PHYS2014: Benton Lecture 16, Slide 6 a) With what velocity does the first ball collide with the second?...
View Full Document

This note was uploaded on 11/28/2011 for the course PSYCH 2014 taught by Professor Staff during the Fall '10 term at Oklahoma State.

Page1 / 30

PHYS_2014_Lecture_16 - Fall 2010 Oklahoma State University...

This preview shows document pages 1 - 7. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online