This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: the number of substrate molecules that are converted to product by one active site when [S] is high relative to K M . called the turnover number v = k cat E [ ] total S [ ] total S [ ] total + K M What happens to the equation if [S] total << K M ? v = k cat E [ ] total S [ ] total K M = k cat K M E [ ] total S [ ] total At really low [S], the rate is dependent on [E] total and [S] total k cat /K M is a secondorder rate constant describes the enzymes efFciency . called the speciFcity constant . k cat (s1 ) K M (mM) k cat /K M (M1 s1 ) Sub. 1 1,000 10 1 x 10 5 Sub. 2 10 0.001 1 x10 7 Example: A hydrolases activity is measured with two different substrates. The k cat and K M results are below. Which substrate is the better one for the enzyme?...
View
Full
Document
This note was uploaded on 11/28/2011 for the course CHEM 340 taught by Professor T.baird during the Fall '11 term at S.F. State.
 Fall '11
 T.Baird
 Chemistry, Enzyme, Kinetics

Click to edit the document details