364e1 - ME 364 - Kinematics NAME 519 L (77' [Wu Spring...

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Unformatted text preview: ME 364 - Kinematics NAME 519 L (77' [Wu Spring Semester, 1998 Exam 1, 100 Points, Open Book 1. (20 Points) The quick return mechanism is shown one half of full size. In the position shown, the slider 6 is moving to the right at a speed of 10 inches per second. Determine the required angular velocity of the crank (link 2) and the resulting angular velocities of links 4 and 5 +35 w [9.6 _ [‘79 d {I JJWmfi Fjw;:bgé:$f§(:73r%ql annmqfifl " (2:46 er I I (b) all, 1 ‘rl ea _-; JWw/f ‘ 7Tb! 3 53‘" porn I ‘ l! 0", 47¢, 0 (Ur [’54 —'7 a“, 4/ : M’s-r, , 95—4., : . “' ' I/fl «5334 um“... 51 are," MAE 364 - Kinematics, Spring 1999 Exam 1 Page 2 2. (20 Points) Determine the locations of all of the instant centers in the mechanism below. Clearly identify the location and identity of each one. Location accuracy is part of the grade. 0F: 1‘0" ‘0 - RUM)? 102—?(0/ 0F: 3 (WM (51%} Wm; DF=3(9‘//- a[:—+/_)-I{3} v/{x/ :f-l-/§-];f ;y_g_3_l = fl era-f ll "h. MAE 364 - Kinematics, Spring 1999 Exam I Page 3 4. (15 Points) The disk shown is made from steel ( p= 8000 kg/m3). Determine the mass moment of inertia of the member about the axis GG (going through the mass center). I: wéofiafgflm/ ‘ WWWJZZW) : 000799 = .00093% a 4 , ' _L.‘ :1 r1, : mm (am M2 = M "W m i a, 1/ k; = JWW : Mm —» 90%?) I : TIE/1,1") Ifif/‘fir‘qtflglc/é 3 old—57W 39:13:3/ ,. a . , . 2 — . : flex/)0?” = inept:in 3:247”) :LOM k/Mi l : 0W7}? 1&me = w, 3,; 4— 4512,)?” "'_'"" 2 I 5 '0”? #7” : 5-4479” Harm/1' ltd/fit = duff - é/{J’fl/é/ : 4.77/54 9» 5. (10 Points) If the disk in the previous problem is suSpended on a knife edge through one of its holes. what will the period of oscillation be? %MM@ 1: Aaféflfiyfiw f4: ¥¢d7kj at I”: 1+ Mr‘ um ; 49%)?(40) : QKJJHY k;me - u A”; 4" T: arr 3.2a c 4/7 4‘” y 7 r , 7%; MG ' Mfr flaw/5; 6Wm,wm 7: , 7V520C, U MAE 364 - Kinematics. Spring I999 Exam I Page 4 6. (20 Points) Determine the corrections that must be placed in balancing planes A and B to dynamically balance the system shown. _ (mafia : t #1 (nut)1 = 0.15 kg m Ba: v— 9 " {35w (mr)b= {016 ~' {2'3"J (30? ’7 eh: I ’15. ,Mo “'40 "3 I. 2 ,w ‘W’ 50 10 —3.9M 43%? my ’ My? 3 Jam 70 W7 I95 0 MW ' _’ 0 7 HM _3,/f6_ Linda‘s—“'4 —-"'""w ’1) fl )1; 12 & Mm Mrncfiaf mnmafi I 3/; 12:? W A; -—/0.5” $549” 'M Ma 70 W “(#7543 43/557 Com m m fl ' —- .040 :3 3 W W Mar '1'; 17;??? IZJKSJ~AJH ‘9 mm: {5.564339 Mm fffl/ ...
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364e1 - ME 364 - Kinematics NAME 519 L (77' [Wu Spring...

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