E1_05M_s - ME 364 Kinematics NAME I 071 Summer Term 2005...

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Unformatted text preview: ME 364 - Kinematics NAME I / 071/ Summer Term, 2005 ‘ Exam, 100 Points, Open Book 1. (15 Points) Determine the locations of all of the instant centers in the mechanism below. Clearly identify the location and identity of each one. Locatin accuracy is part of the grade. 2. (15 Points) The quick return mechanisnibglow is showd\one half of full size. The cranktlink 2) is rotating counterclockwise at a rate of 40 radiansper second. ‘Petermin the velocity of slider 6, the angular velocity \ of link 4, and the linear velocity of point 3‘ Be sure to includ both magnitude and direction. \ \ (a) v6: elf/~15“ (7515A) \\ (b) m4: lira/g; (c) VB: M’Mf [HM/ 4/ ' : Onflw wl = (2mm) M 1' n?.5’{’m/re [Ii/5d)?” = 7&14/5 l/m-F and” #4 =07. 75v.» (/0 5 BMW-fi/ tuft/M - Md, Maw/,9 — Xflfmhxa) . ‘ afar ( (,4, . V3: WW5. r<37:4X/7.?) -‘ /:33”é¢ 79 , W, ,,,, ,, _, ,,,, , , _ g / MAE 364 - Kinematics Exam — Summer Term, 2005 Page 2 3. (20 Points) The mechanism is shown one half of full size below. Link 2 is rotating clockwise at a rate of 1.30 radians per second. Determine the angular velocities of links 3 and 5. v 1"=1 in/s or 1mm=1mmls Work Here: 0 VASJJM w}:st M25),th s[35’xt)/.3 1' @ IM/C flf 3 7" ipfl} : Vfi’f/ : 99rd D (op/w W; 3;; WM 4 (‘9 "V53 : v‘éfl V3345 MAE 364 - Kinematics Exam — Summer Tenn, 2005 Page 3 J 4. (10 Points) Determine the degrees of freedom in the following kinematic chains (show your work to receive credit!) 1‘0"} be r a Rolling\ (bDF= 9. (cw 0F: 3(7—/)~a(cu)«/(//—/{a/ M: :Véq)‘ May/)vw/‘l/fl/ : ISA/4" 1 3 0f:3(;-l/"Q(3+l)v(l)l~tl.[/j 3 /f—/é/ : m- 8—7-/ V I 5. (10 Points) Determine the corrections that must be placed in balancing planes A and B to dynamically balance the system shown. A Balancing Planes I} (ma = M m #1 V ’ \fl ea = _ J- 1/0 “’2 —£— ‘bearing (ml')2 = 0.15 kg m (mob = .92). kg‘m . 0 6b - W MW; flél/M/f B 1*, mr 6 L w M” mfg “MI/‘6 Carracf/Iu m A ‘T 71/ ‘57 a #0 16 v.0 MW (6% W7") 3. [5' w l 70 I35 ‘ 45.5w 0 Am QM.“ Cilia “7”” 40 ll 9,104 —//,276 z ii; 3 '3 4,394 M724» Mr: L759; = ./57 éfo [MM-474 «hi 5 . fl ‘ at Mr” Mchjé mar/a r E A g 7“; \f- 0 VA/ ,1. Confer/m ,4 fix 1’ (j? [:00 ‘9‘0 3 —3 0 (Jam/2, 2:724) a 3 '3' —7d 70 l" w 47,739 Mra: Q‘HM M, ?I ‘31739 ‘ [06 ‘ "V" 775’ : ,aw 4/00” MAE 364 - Kinematics Exam - Summer Term, 2005 6. (20 Points) Using the complex number approach, analyze the mechanism shown. (a) Determine the series of scalar equations which must be used to solve for the F - follower (Link 3) velocity assuming that the distance AB, the angular position 9 , and angular velocity co of Link 2 are known. (Box each equation in the answer) (rides in slot of Link 3) Sinfe )/ /~5 flarrgar/u/c) /”1 h } If my UM} (/9 _"'— Ve/M/ Pd/ In Meflo/ . W 0 V109: WW4 : ://ZflA/fl; g 25’": / V w _ .n/ x/ x/ /\ ‘ Maw " "4’" w“ - gawk/m @ VP; : Vl’q 7L (/Ps/Pa V - ’7 carnal/fl: ‘_ :t/JM, / ” m“ in? “I‘M/f0 “’4’ JM’“% :3 &&n%fl ...
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