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# e2_00m_s - ME 364 Kinematics NAME 50" 0 77M Summer Term...

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Unformatted text preview: ME 364 - Kinematics NAME 50" 0 77M/ Summer Term, 2000 Exam 2, 100 Points, Open Book \ Input Gear 1. (10 Points) Determine the speed and direction of the \ output gear. The input gear rotates at exactly 500 rpm clockwise. Output Gear (I. My“, f V W/< MA (IV/n W4 [VIC {— d M = at (My) = 5,25“ .10 . , . K 2. (25 POlnts) Determme the rotatlonal speed of 64 tooth sprocket C 60 T 50 tooth worm ear - - X E 45 T g the output shaft. Is the show 1re correct? Double Threaded y 16 tooth sprocket J J Worm L€# #4416/ x ’ - n k n w w: ﬂ : 3’1— ” ﬁ 92“ 0 .5”; WM wx Wk , y 10,; We ’c ‘02; E I / l I / , 4r 9:6 .‘f/i 'Z/ﬁ Liar!) WF oa/rr 160,} (We MMﬁﬂWﬂﬁm .4, ’ _ Nyﬂg ”a NEE/VT IVA 7,14 ; 64 muggy o1 all. ~3fé/§,o/mé 7;” M w 917 3; 3y 3‘5 3;“ MW ,2 Wm : ,o/ga'd/iw/ : 2157/”? MAE 364 - Kinematics, Summer, 2000 Exam 2 Page 2 3. (40 Points) The mechanism is shown ne half of full size 10w. Link 2 is rotating clockwise at a rate of 1.00 ' radians per second and speeding up at a rate of 0.50 radians per second per second. Determine the angular velocities and angular accelerations of links 4 and 5 and the linear velocity and acceleration of link 1":1 in/s or C. 1 mm=1 rnm/s £0 .. @35/ 5 — II ' V6 = M 07/!) A W = .Mgw a5 = ' I’ll/g J. m . a6 = (715—012: :?(/l717/,2/ L/gZaafz , mm a) a,” , m; moi/5W l/ = Awrﬂhif 0) I42. 2 A [/ aﬂfsﬂMﬁm’j’Bﬂ @ V“ 172;“ A - A ﬂ/ﬁ ~ ‘ _ ,, 7 ,1 r M , 3‘ ‘ ‘ 9r : at 9 6/ “M'gaﬁﬁ’lﬂovﬁMm/m ”my tam/14L” 3/4 My G) I’mﬂe a ‘/ fajafb’ 32‘: Qﬂ’ /— \V L ”a M (331,117: 3 K N d/ X“ a :70 3K3” M:——=[UK/ a .> , @ VC: (/5 +l/C/g M, ' R fl (yr/Maya 0+ 9 +07e-ﬁ/53 5/”0 f ‘ ( A + r ) M9- 1411. 1' ”mg/g: @( 6 +40) ’ (1b., * “W: “(/3 0V4 W “W 92 . 513: 47/ I 4 “1;” %:1—7‘7:1/quy{ (7 3c. II 5 MAE 364 — Kinematics, Summer, 2000 Exam 2 Page 3 4. (25 Points) Determine the acceleration of the follower in the position shown assuming that the rate of rotation of the cam is constant at 200 rpm. The mechanism is full size. : : : a Z ' Make an grand/947‘ méﬂé‘I/in (l 5‘ emf/é» Raf: r4/ I 7 W%..% {413\$ ‘ ”gm“ C. 112/0032 Ana/515W; L V5 =W% : s7(M,‘75/) = ﬁfm%<—~ Jt/ {V 1).. f4)“: (60‘) l/Pq/p-L Ft 56¢ / ﬁr ’1 5 “- 5g) 1 + (or t 7" ‘I ﬂ ’4 . lzg+ﬂﬂj a}; ﬁ/i/l?» Fig/ﬂ fag/01 0. a 0 km K, A {7 07' Imn=QW71 (ll/p94, (1/4: 9(572’720J7/ ‘7) 61/3,: g a : Afl)opnn/,R (HA2) 4/1 I gym ...
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