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hw05_sol

# hw05_sol - Solution to EE 4770 1998 Homework 5 Problem 1...

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Solution to EE 4770 1998 Homework 5 Problem 1: Event and handler information from problem: Event Strong Weak Handler Event Name Prior. Prior. Run Time Timing A 3 2 5 μ s Periodic, 15 μ s B 3 1 4 μ s Periodic, 22 μ s C 2 2 (28 + 2 c ) μ s Periodic, 100 μ s D 2 1 400 μ s Periodic, 1 ms E 1 1 60 ms At initialization and 50 ms after each response. Solution: Event Load Set Load Fact. Loaded Dur. Latency Run Response Load A 1 5 μ s 4 μ s 5 μ s 9 μ s 0 . 3333 B 1 4 μ s 5 μ s 4 μ s 9 μ s 0 . 1818 C 1 (28 + 2 c ) μ s 834 μ s 103 μ s 928 μ s 0 . 0760 D { A, B } 0 . 485 825 μ s 71 μ s 825 μ s 896 μ s 0 . 4000 E { A, B, C, D } 0 . 008848 6 . 7808 s 928 μ s 6 . 7808 s 6 . 7818 s 0 . 0088 Total Load: 0.9999 Events A and B , sharing the highest strong priority level can only delay each other and at most for one run. (That is, event A never has to wait for 2 B ’s, and vice versa.) To find the latency, run time, and response time of A use event sequence B , A . To find the latency, run time, and response time of B use event sequence A , B .
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