Exam 3v2 Answers, 5/17/2011, ECSE-2500, Engineering Probability, RPI (Eng Prob Spring 2011)
5/18/2011 1:49:34 PM
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ECSE-2500 Engineering Probability, RPI, Spring 2011 Home Page
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the first ones.)
We record the order in which you hand in your exam the
better to keep track of the exams, and sometimes to
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Blue marks an answer.
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Numbering error: There were two question #1
1. [_____/10] Evaluate and give me the answer as an expression perhaps involving
. Show your work.
is a Gaussian pdf with
and integrates to 1. So,
Random variable X is continuous U[0,2].
Random variable Y is continuous U[0,3].
Random variable Z is continuous U[0,4].
Random variable W
You could do it the detailed way. Or, you could notice that min(X,Y,Z) <=2 and so P[0<W<3]=1.