MA 36600 LECTURE NOTES: WEDNESDAY, MARCH 43Newton’s Second Law of Motion states thatF=m a. That is,m u= sum of forces =Fg+Fs+Fd+Fe=m g−k(L+u)−γu+F(t)Sincem g−k L= 0, we can rewrite this asm u−k u−γu+F(t)=⇒m u+γu+k u=F(t).Hence the positionu=u(t) satisfies a linear second order differential equation. Note that in general, if we
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