This preview shows page 1. Sign up to view the full content.
Unformatted text preview: Total number of blocks that can be stored = 2400 * 12 / 1.25 = 23040 Thus the total number of records that can be stored = 3 * 23040 = 69120 records. b) With no blocking, 400 / 1600 = 0.25 is spent for the record in each block and in this case the number of interblock gaps is equal to the number of blocks. Thus, for each block (record + IBG) 0.25 + 0.5 = 0.75 is spent. number of records that can be stored = 2400 * 12 / 0.75 = 38400 records....
View Full Document
- Spring '11