# week5 - HASHING Static Files Expandable Files Still we can...

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HASHING Static Files Expandable Files Still we can add, Extendible Hashing delete records Linear Hashing Dynamic Hashing 0 Hash Function Key m-1 HF = mod(key,m) HF(ki)=HF(kj) ki != kj collision We must find a collision resolution method Prime Data Area Overflow Area A bucket has several blocks. It can store many blocks as long as we have room for a new record collision is no problem.

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Example: Bkfr=3 (Bucket Factor) HF=mod(key,5) Key values : 35, 71, 33, 19, 22, 60, 42, 46, 47, 17 Key HF=mod(key,5) Collision(N/Y) Prime Overflow Data Area Area 35 60 35 mod (35,5)=0 N 0 71 mod (71,5)=1 N 71 46 33 3 N 1 19 4 N 17 22 42 47 47 22 2 N 2 60 0 N 33 42 2 N 3 46 1 N 19
47 2 N 4 17 2 Y To decrease number of collisions keep prime data area size > the number of records to be inserted to the files. N number of records in file LF= M x Bkfr Bucket Factor Load Factor LF= 10= 0,66 %66 5x3 T F =one disk access = s + r + dtt Time needed to read one bucket X: Average overflow chain length T F(successful) = s + r + dtt + (x/2) * (s + r + dtt) T F(unsuccessful) = s + r + dtt + x * (s + r + dtt) Lower load factors means less collision and shorter access time. Large bucket factor also means less overflow. X=10 T F(successful) = 1 + 5 = 6 T F(unsuccessful) = 1 + 10 = 11 File needs reorganization if we have many records in the overflow area

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