MSE+302+Problem+Set+1_Solutions

MSE+302+Problem+Set+1_Solutions - MSE 302 Problem Set 1...

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MSE 302 Problem Set 1 Solutions (37 Points) 1. (10 Points) Excel file solutions are on the course website. To calculate the fraction of incident light absorbed at each wavelength using an absorption coefficient, we can use Beer’s law: ) exp( 0 t I I α = , Fraction absorbed 0 1 I I = So for a given thickness, we can generate an absorption spectrum, i.e. a column for the fraction absorbed for every single wavelength (“spectrum” in this class is anything as a function of wavelength), then multiply this column by the AM1.5G spectrum in flux units (or current units), and then integrate or sum this product to get the total photon flux (or current) for that particular thickness. To convert the AM1.5G spectrum from energy flux to # flux, we just need to divide by the energy per photon: λ hc E photon = , and to get current, multiply by the charge per electron: , this should give amps/m C q 19 10 6022 . 1 × = 2 Some people were confused about the nm -1 units in the solar spectrum data. This is the increment over which the solar power was given in the Excel spreadsheet. Another way of saying this is that it tells you that the power given for that data point is the power from all of the photons incident within a bandwidth of 1nm. So you do
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MSE+302+Problem+Set+1_Solutions - MSE 302 Problem Set 1...

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