week2 (dragged) 59

week2 (dragged) 59 - Cross product i j k c= a b = det a1 a2...

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! The magnitude of the cross product can be interpreted as the positive area of the parallelogram having a and b as sides Cross product 50 a × b =det ij k a a 2 a b 1 b 2 b
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This note was uploaded on 12/01/2011 for the course PHYS 241 taught by Professor Wei during the Fall '08 term at Purdue.

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