Rate%20Law%20Answers0

Rate%20Law%20Answers0 - 2 H 2 or the production of C 2 H 6...

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CHEM 1212 Rate Law Practice For a reaction of: 2 H 2 + C 2 H 2 C 2 H 6 You have the following experimental data: Rate [H 2 ] [C 2 H 2 ] 0.150 0.0100 0.0100 2.400 0.0100 0.0400 2.400 0.0300 0.0400 1. Determine a rate law for the above reaction including a value for k. As [C 2 H 2 ] is multiplied by 4, the rate is multiplied by 16, making it second order. As [H 2 ] is tripled the rate does not change. Rate = k [C 2 H 2 ] 2 0.150 = k [0.01] 2 k = 1500 Rate = 1500 [C 2 H 2 ] 2 2. Which chemical in the reaction does the term “rate” describe? Rate can refer to the consumption of C
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Unformatted text preview: 2 H 2 or the production of C 2 H 6 as they have a coefficient of 1 3. Solve for the units of k? Rate = k [C 2 H 2 ] 2 Mol / L-s = k [mol/L] 2 Mol / L-s * [L/mol] 2 = k k = L / mol-s 4. Solve for the rate of the reaction if [H 2 ] = 0.250 M and [C 2 H 2 ] = 0.250. Rate = k[C 2 H 2 ] 2 = 1500 * (0.25) 2 = 93.75 mol /L-s 5. What is the initial rate of H 2 under the conditions in problem 4? Rate = Rate(H 2 ) CHEM 1212 93.75 = Rate(H 2 ) Rate(H 2 ) = 187.5 mol/L-s...
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This note was uploaded on 11/29/2011 for the course CHEM 1212 taught by Professor Dockery during the Fall '08 term at Kennesaw.

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Rate%20Law%20Answers0 - 2 H 2 or the production of C 2 H 6...

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