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# Test%203%20Topics%20final%20slide - -14 equation Now...

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Write a neutralization reaction for HClO with NH 3 HClO ( aq ) + NH 3 ( aq ) --> NH 4 + ( aq ) + ClO - ( aq ) It helps to identify what the acid is and what the base is in the reactants to determine the products. Once the acid is identified, just have it give the H + to the base. Determine if products or reactants are preferred in the above reaction if K a (HClO) = 2.9 * 10 −8 and K b (NH 3 ) = 1.76 * 10 −5 . HClO ( aq ) + NH 3 ( aq ) --> NH 4 + ( aq ) + ClO - ( aq ) Acid Base Conj Acid Conj Base K a K b K a K b 2.9 * 10 -8 1.76 * 10 -5 5.7 * 10 -10 3.4 * 10 -7 Find the K for every chemical in the reaction (as done above). Determine the K for the conjugates using the K a * K b = 1 * 10
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Unformatted text preview: -14 equation. Now, determine which side would be the weaker. The 10-8 and the 10-7 are very close, and can be considered almost a tie. The 10-5 versus the 10-10 is a huge difference, with the advantage being that the left side (10-5 ) is much stronger. Since reactions favor the weaker pair, we'll go with the right side. The 10-10 is far and away the weakest component in this reaction. Note: Any examples you would have to do would have a big difference like this one. I wouldn't give you one where every chemical had a K on the order of 10-6 for example....
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