MIT2_017JF09_p13 - 13 NUMERICAL SOLUTION OF ODES 13 28...

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13 NUMERICAL SOLUTION OF ODE’S 28 13 Numerical Solution of ODE’s In simulating dynamical systems, we frequently solve ordinary differential equations. These are of the form dx = f ( t,x ) , dt where the function f has as arguments both time and the state x . The time argument is used if the system is time-dependent (time-varying), but unnecessary if the system is time-invariant. Solving the differential equation means propagating x forward in time from some initial condition, say x ( t = 0), and typically the solution will be given as a vector of [ x (0) ,x t ) ,x (2Δ t ) , ··· ], where Δ t is a fixed time step. The Taylor series is used to derive most of the simple formulas for solving ODE’s. The general Taylor series expansion of the generic function g in two variables is g ( t + Δ t,x + Δ x ) = g ( t,x ) + ∂g ∂t Δ t + ∂g ∂x Δ x + 1 2! 2 g ∂t 2 Δ t 2 + 1 2! 2 g ∂t∂x Δ t Δ x + 1 2! 2 g ∂x∂t Δ x Δ t + 1 2! 2 g ∂x 2 Δ x 2 + ··· . In the above formula, when the arguments of g and its derivatives are not shown, we mean that it is to be evaluated at ( t,x ), that is g alone means g ( t,x ) and so on. We use this shorthand below in several places. The simplest of all the ODE methods is forward Euler , created by setting g = x and looking only at the first two terms on the right-hand side of the Taylor series: x ( t + Δ t ) = x ( t ) + dx dt Δ t = x ( t ) + Δ tf This formula says that x at the next time instant is the current x plus the time step times the slope evaluated at the current x . Referring to the Taylor series, we see that the forward Euler does not do anything with the second-order terms (Δ t 2 and beyond), and so we say the method is second-order accurate in the step, which will turn out to be first-order accurate when you solve a real problem with many steps. First-order means that if you halve the time step, you can expect about half the error in the overall simulation. An alternative, the Runge-Kutta methods are popular workhorses, and implemented in the MATLAB commands ode23() and ode45() . Let’s take a look at the first of these: The rule is k 1 = Δ tf k 2 = Δ tf ( t + Δ t/ 2 ,x ( t ) + k 1 / 2) x ( t + Δ t ) = x ( t ) + k 2 We see that k 1 is the same change in
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This note was uploaded on 11/29/2011 for the course CIVIL 1.00 taught by Professor Georgekocur during the Spring '05 term at MIT.

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MIT2_017JF09_p13 - 13 NUMERICAL SOLUTION OF ODES 13 28...

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