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Unformatted text preview: f ( ω ) + X ( ω 1 ) f ( ω 1 ) + X ( ω 2 ) f ( ω 2 ) + X ( ω 3 ) f ( ω 3 ) = (0) f ( ω ) + (2) f ( ω 1 ) + (10) f ( ω 2 ) + (50) f ( ω 3 ) = (2)(1 / 100) + (10)(1 / 1000) + (50)(1 / 10000) = . 035 = 3 1 2 cents Part 2. Now suppose that on Mardi Gras, 1 in ten tickets wins two additional tickets in the same lottery. What is a ticket on Mardi Gras worth? Solution. Let ω 4 be the event of getting the bonus Mardi Gas ticket. If E ( X ) = e , then X ( ω 4 ) = 2 e . e = E ( X ) = X ( ω ) f ( ω ) + X ( ω 1 ) f ( ω 1 ) + X ( ω 2 ) f ( ω 2 ) + X ( ω 3 ) f ( ω 3 ) + X ( ω 4 ) f ( ω 4 ) = (0) f ( ω ) + (2) f ( ω 1 ) + (10) f ( ω 2 ) + (50) f ( ω 3 ) + (2 e ) f ( ω 4 ) = (2)(1 / 100) + (10)(1 / 1000) + (50)(1 / 10000) + (2 e )(1 / 10) e = . 035 + e/ 5 e = . 04375 = 4 3 8 cents 1...
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This note was uploaded on 11/29/2011 for the course MATH 3355 taught by Professor Britt during the Spring '08 term at LSU.
 Spring '08
 Britt
 Probability

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