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cee100-fa10-mt1-Stacey-soln

# cee100-fa10-mt1-Stacey-soln - CEt 00 Midterm Examination...

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Unformatted text preview: CEt 00 Midterm Examination Fall 201 0 Friday, October 1 , 2010 Name 8 Z’ Student LD. This exam is open book and open notes. You will be given fifty (50) minutes to complete two problems. Space is provided on each page for your soiution, the back of the pages may also be used. Note that the first problem is worth 40 points and the 2”d is worth to; allocate your time accordingiy. State clearly any assumptions you use in the solutions. Good Luck! For reference: Atmospheric Pressure = patm = 100 kPa Gravitationai Acceleration = g = 9.8 m/s2 Problem 1 (40 points): The set of tanks shown in the following diagram is designed to intermittently fill a water bowl for a pet dog during an owner's absence. The system consists of two tanks, connected by a small connecting pipe, and the water bowt. The first tank is maintained at a constant depth, H1 2 0,15 m. The right-hand—wall of the second tank is hinged at the top, with a locking mechanism that can resist a moment of M0 = 265 Nm. When a ' counter—clockwise moment larger than M0 is applied around the hinge, the wall will open momentarily and allow all water in tank 2 to drain out into the water bowl. Tanm _ Tank2 Water Bowl Additional measurements include: Depth of tank 1 (constant): H1 = 0.15 m Surface area of tank 1: A1 = 0.0625 m2 Surface area of tank 2: A2 = 0.0625 m2 l Cross-sectionai area of connecting pipe: Apipe = .0001 m2 Height of the hinge above bottom oi tank 2: L = 0.25 m Width of each tank into the page: W = 0.25 m Assuming that the second tank starts empty and that water is added to the first tank to ensure H1 is constant: (a) Determine the depth of water in tank 2 when the gate opens. An exact soiution to the equation is not necessary, an estimate to the nearest 5 cm is sufficient. (b) lnitlaiiy, tank 2 is completely empty. For this condition, determine the velocity of flow going from tank 1 to tank 2. (0) Based on your answers to (a) and (b), you can define an estimate for how long it will take for thewalt to open by assuming the veiocity calculated in (b) is constant as tank 2 fiiis. In reality, wilt it take a longer or shorter time (than an estimate based on constant velocity) for the wall to open? Explain your reasoning. NCMFQV" Lib; m -. Mmmﬁvh‘s ‘CIL‘MK ﬁgp~£¢m 0 {rm/L 1* Cam—7% [TL-F [A ’L‘. a we ‘1) v I Z , (/Igﬁr 2.1+ t¥ 721—} {ﬂ 0 vi V1: “6% O { cu )2 I 7 {mild WWI/hm) '12 — u; k ,v “(A A?) ? [3} [£045 CkriLiQAJz/pgcg b 90LQ7CPOK / MM LL WOL'jxs +0 ck CLQ ELL 0.53.12. Cy debt ail—.1 VIL {Rd/r! {bib {Mufkég 2:3) Problem 2 (1 0 points): A verticai pipe carrying flow Q = 0.5 mars downwards has an expansion from D1 = 0.5 m to D2 =1 m: """ "Q" "um" 21 2 m, D; m- Q = 0.5 m3/s Use Euler‘s equation to determine the pressure differenoe between points 1 and 2. Could you have used the Bernoulli equation to do this calcuiation? Why or why not? “3% Sicmﬂﬁ Hues rl) q}: w%% \Uvev: O) :5 09: gig) E” “ST? igifiitw t em) 3) wzewm Veg ‘E/QMWR'S "[5 Gig. Ch S‘kEcW/I‘M/ ...
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cee100-fa10-mt1-Stacey-soln - CEt 00 Midterm Examination...

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