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Unformatted text preview: v S = 12 V,i S = 8 mA,R = 6 k ,L = 10 mH,C = 2 F (a) (5pts)Determine the steady state value of the capacitor voltage. The capacitor acts as an open circuit. The controlling variable, i X ( ) = 0 and the dependent voltage source is zero (short circuit). In steady state the inductor acts as a short circuit. Hence the capacitor terminals are short circuited. v C ( ) = 0 Prepared by Dr. Jorge L. Aravena. Last revised on December 8, 2000 2 (b) (5pts)Determine the steady state value of the inductor current. All the currents f ow through the inductor. Use source superposition, for example. i L ( ) = i S + v S R = 8 mA + 2 mA...
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This note was uploaded on 12/01/2011 for the course EE 2120 taught by Professor Aravena during the Fall '08 term at LSU.
 Fall '08
 ARAVENA
 Volt

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