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test1fa00_sols

test1fa00_sols - Test 1 Fall 2000 A IS Wo = VAB I AB The...

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A B The source delivers W o mW of power. If I AB = I o mA V AB = ________ Point ____ has higher voltage than point _____ (A/B) In the source, positive charges move from ____ to ____ I S Test 1 Fall 2000 ] [ ] [ mA I mW W V I V W AB O AB AB AB o = = Hence Vab has units of Volt W mW O [ ] I mA AB [ ] V V AB [ ] 200 25 -8 100 10 -10 200 10 -20 100 20 -5 Vab<0 B A Iab>0 A B

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A B R (sec) 0 ]; [ ) ( = t mC e Q t q t o The positive charges crossing point A are given by Find I AB = ________ Find the instantaneous power absorbed by the resistor at t =1 sec P R (1) = __________ The total energy absorbed by the resistor is E R = _________ R = 5k Q o = 5mC Terminal ____ has higher voltage than ____ Test 1 Fall 2000 0 ], [ ) ( = = t mA e Q t dt dq I t o AB 2 2 0 2 ) 1 ( ) 1 ( = = e RQ RI P AB R R is kOhm, I is mA. Hence P is mW Q is in mC, time is in sec current is in mA 2 0 2 2 2 0 2 0 2 1 2 1 ) ( o t o R t o R R RQ e RQ E dt e RQ dt t P E = = = = Power s in mW. Time is in sec. Hence Energy is in mJ Iab is negative. Charges move from B to A. R is passive. Hence B has higher voltage. P = VI, current, Iab, is negative, power is positive. Hence Vab must be negative. Point B must have higher voltage
+ - I S 4k 8k I x aI x 2k 6k A B I S = __mA, a=__[V/mA] V AB = _______ Test 1 Fall 2000 Ix can be determined using a current divider form ] [ 3 1 8 4 4 mA I I k k k I S S X = + = 1 2 At the dependent voltage source ] [ 3 ] [ ] / [ 12 V I a mA I mA V a V S x = = Vab can be determined using a voltage divider form

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test1fa00_sols - Test 1 Fall 2000 A IS Wo = VAB I AB The...

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