test1fa00v1

Test1fa00v1 - AB = Find the instantaneous power absorbed by the resistor at t = 1 sec P R(1 = The total energy absorbed by the resistor is E R = R

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1 EE2120 TEST No. 1.v1 September 14, 2000 NAME (please print) SSN INSTRUCTIONS Failure to follow these instructions may result in your work NOT being accepted for credit. DO NOT OPEN UNTIL THE INSTRUCTOR TELLS YOU All work is individual. Concentrate on your own paper at all times STOP WORKING AS SOON AS THE INSTRUCTOR TELLS YOU When instructed, walk to the front and leave your work on the instruc- tor’s desk If you finish ahead of time, walk to the front and leave your work on the instructor’s desk SHOW ALL YOUR WORK IN EACH PROBLEM
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Prepared by Dr. Jorge L. Aravena. Last revised on September 14, 2000 2 (15 pts) A B The source delivers 100mW of power. If I AB = 20mA V AB = ________ Point ____ has higher voltage than point _____ (A/B) In the source, positive charges move from ____ to ____ I S (20pts) A B R (sec) 0 ]; [ ) = - t mC e Q t q t o The positive charges crossing point A are given by Find I
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Unformatted text preview: AB = ________ Find the instantaneous power absorbed by the resistor at t = 1 sec P R (1) = __________ The total energy absorbed by the resistor is E R = _________ R = 10k Q o = 10mC Terminal ____ has higher voltage than ____ Prepared by Dr. Jorge L. Aravena. Last revised on September 14, 2000 3 (20pts) +-I S 4k 8k I x aI x 2k 6k A B I S = 12mA , a=3[V/ mA ] V AB = _______ Prepared by Dr. Jorge L. Aravena. Last revised on September 14, 2000 4 (25pts) I S I 1 6k 6k 6k 1k 4k I 2 I 5 I 4 I 3 I S = 12mA , I 1 = 4mA I 2 = _______ I 3 =_______ I 4 = _______ I 5 = _______ V AB = _______ A B Prepared by Dr. Jorge L. Aravena. Last revised on September 14, 2000 5 • (25pts) _ + 8k 4k 12k R V S V S = 24V , R = 6k I o I 1 I o = ________ I 1 = ________ P R = ________ (P R is the power dissipated in the resistor R)...
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This note was uploaded on 12/01/2011 for the course EE 2120 taught by Professor Aravena during the Fall '08 term at LSU.

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Test1fa00v1 - AB = Find the instantaneous power absorbed by the resistor at t = 1 sec P R(1 = The total energy absorbed by the resistor is E R = R

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