test4sp01_sols

Test4sp01_sols - KVL v(t = v L(t vC(t di 1t v(t = L(t i x)dx dt C −∞ 10 cos 20t 0.2 × 20 i(t = 10 sin 20t v(t = 0.1× 200 cos 20t − i(t = 10

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Unformatted text preview: KVL : v (t ) = v L (t ) + vC (t ) di 1t v (t ) = L (t ) + i ( x )dx dt C −∞ 10 cos 20t 0.2 × 20 i (t ) = 10 sin 20t v (t ) = 0.1× 200 cos 20t − i (t ) = 10 cos 20t v ( t ) = −0.1× 200 sin 20t + 10 sin 20t 0.2 × 20 v (t ) = CIRCUIT FOR t<0 R1 VS v (t ) R2 + - R2 Vs , t < 0 R1 + R2 i L (t ) = VS , t <0 R1 + R2 CIRCUIT AT R1 v (∞) CIRCUIT AT t=0+ R1 v(0+) t =∞ R2 R2 Vs(V) R1(kOhm) R2(kOhm) R3(kOhm) iL(0) v(0-) R1||R3 v(0+) R2||R3 v(ss) 46.00 20.00 3.00 5.00 2.00 6.00 4.00 1.20 1.88 3.94 36 18 6 6 1.50 9.00 4.50 2.25 3.00 5.14 R3 R3 Vs + - iL (0−) Vs v ( 0 + ) − Vs v (0+ ) KCL(0 +) : + i L (0 −) + =0 R1 R3 + - v (∞ ) = R2 || R3 VS R1 + R2 || R3 C = 20µ F v 0 ( t ) = K1 + K 2 e − t τ ,t > 0 K1 = v 0 ( ∞ ) = 0 1 K1 + K 2 = v 0 ( 0 + ) = v C (0) 2 t − 1 v 0 ( t ) = v C ( 0)e τ , t > 0 2 RTH = 2 R || 2 R = R τ = RTH C CIRCUIT IN STEADY STATE + v 0 (∞ ) − v0 (∞ ) = 0 R(kOhm) C(uF) v_c(0)(V) Tau(s) v_0(ss) K1 K2 6.00 20.00 12.00 0.12 0.00 0.00 6.00 τ= R R Vs(V) R(Ohm) L(H) I(ss) R_th(Ohm) Tau(s) K1 K2 CIRCUIT IN STEADY STATE i1 R i 2 R V1 R VS + - R/2 V V1 = VS = S R + R/2 3 i (∞) CIRCUIT REDRAWN i1 R 40.00 10.00 0.20 5.333 6.000 0.033 5.333 -5.333 R i (∞) = i1 + i2 i (∞) = Vs + Vs R 3R VS R + - R V1 i2 R L RTH R RTH R 3 RTH = R || ( R + R / 2) = R 5 di τ ( t ) + i ( t ) = i (∞ ) dt i ( t ) = K1 + K 2 e − t τ , t >0 K = i (∞ ) K1 + K 2 = i ( 0 + ) = 0 t æ −ö i (t ) = i (∞)ç1 − e τ , t > 0 ç è ...
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This note was uploaded on 12/01/2011 for the course EE 2120 taught by Professor Aravena during the Fall '08 term at LSU.

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Test4sp01_sols - KVL v(t = v L(t vC(t di 1t v(t = L(t i x)dx dt C −∞ 10 cos 20t 0.2 × 20 i(t = 10 sin 20t v(t = 0.1× 200 cos 20t − i(t = 10

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