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DesignAndApplicationsSp03(2pp)

DesignAndApplicationsSp03(2pp) - HEART PACEMAKER LEARNING...

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LEARNING APPLICATION HEART PACEMAKER SCR v SCR i 5 1 Simplified SCR model SCR “fires” A 50 Charging phase As soon as the SCR switches off, the capacitor starts charging. Hence, assume 2 . 0 ) 0 ( C v 0 , ) ( 2 1 t e K K t v t C R RC 6 10 1 6 ) ( K V v C 2 1 2 . 0 ) 0 ( K K V v C 8 . 5 6 2 1 K K 0 , 8 . 5 6 ) ( t e t v RC t C Find R so that the SCR is ready to fire after one second of capacitor charging RC C e V v 1 8 . 5 6 5 ) 1 ( : Required 758 . 1 1 8 . 5 1 RC e RC k R 569 569 . RC THE DISCHARGE STAGE With the chosen resistor discharge starts after one second and the capacitor voltage is 5V 1 , ) ( ) 1 ( 2 1 t e K K t v t C s 569 . 0 V v C 5 ) 1 ( ) ( 10 50 ) ( 10 569 . 0 6 6 ) ( 6 6 A RI v C 45 . 27 5 45 . 22 2 2 1 1 K K K K 1 45 . 27 45 . 22 ) ( 569 . 0 ) 1 ( t e t v t C For SCR turn off 2 . 0 ) 1 ( off C T v s T e off T off 11 . 0 65 . 22 45 . 27 569 . 0 %example6p12 %visualizes one cycle of pacemaker %charge cycle tau=0.569; tc=linspace(0,1,200); vc=6-5.8*exp(-tc/tau); %discharge cycle. SCR on td=linspace(1,1.11,25); vcd=-22.45+27.45*exp(-(td-1)/tau); plot(tc,vc, 'bd' ,td,vcd, 'ro' ),grid, title( 'PACEMAKER CYCLE' ) xlabel( 'time(s)' ), ylabel( 'voltage(V)' ) legend( 'SCR off' , 'SCR on' )
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