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Unformatted text preview: anyway) cancel out since the molecule is symmetrical. CH 3 OCH 3 is a dipole because the C-O bonds are polar and are not symmetrical around the O atom, but this molecule does not have any hydrogen bonds like CH 3 OH, which makes CH 3 OH a stronger dipole than CH 3 OCH 3 . CCl 4 is a non-polar molecule because it is also is symmetrical, so even though the C-Cl bonds are very polar, the bond polarities cancel out due to symmetry, BUT it is a larger molecule than CH 4 (which has similar properties), and therefore CCl 4 would have a higher boiling point than CH 4 . I-Clicker Questions H 2 O: London Dispersion forces and Hydrogen bonding CO 2 : London Dispersion forces NH 3 : London Dispersion forces and Hydrogen bonding CaCl 2 : Ion-Ion forces and London dispersion forces C 8 H 18 : London Dispersion forces...
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- Fall '08