Fall 10 - Name

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Unformatted text preview: Name _______________________________________________________________________________ 1 CHEM 340.01: Biochemistry I Exam 1 September 17, 2010 Part I No. No. No. 1 D 7 C 13 D 2 B 8 D 14 A 3 C 9 A 15 B 4 B 10 D 16 B 5 A 11 A 17 C 6 A 12 B 18 D Part II 19) (36 pts.) N- terminus C-terminus 1 Letter N I N E R S F A N 3 Letter Asn Ile Asn Glu Arg Ser Phe Ala Asn 20) (14 pts.) a) (7/14) D-N-T-P-L-A-Y b) (7/14) pI = 1 2 pK 1 + pK 2 ( ) Net charge a very low pH = +1 (terminal amine and carries a positive charge; everything else is neutral). 1 st proton to leave is terminal COOH proton (0 net charge-this is pK 1 ); next is side chain SH of Cys (this is pK 2 ) pI = 1 2 2.34 + 3.65 ( ) = 3.00 21) (14 pts.) a) (2/14) Arginine b) (12/14) Point on Curve Predominate Ionization State(s) B 2, 8 C 2 E 1 F 1,6 Name _______________________________________________________________________________ 2 22) (10 pts.) Cys − SH Cys − S − + H + Cys-S- is the ionized and active form pK a = 8.18 Answer in calculations:...
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This note was uploaded on 12/04/2011 for the course CHEM 340 taught by Professor T.baird during the Fall '11 term at S.F. State.

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Fall 10 - Name

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