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xt - point t = 0 For negative values of a the graph of this...

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x(t) = 1/2at 2 , where a is a constant. At t = 0 , this object is situated at the origin, but its position changes quadratically with time (since the exponent of t in the above equation is 2 ). For positive a , the graph of this position function looks like a parabola that touches the horizontal axis (the time-axis) at the
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Unformatted text preview: point t = 0 . For negative values of a , the graph of this function is an upside-down parabola. Such a position function corresponds to objects undergoing constant acceleration (which is why the coefficient of " t 2 " has been conveniently written as 1/2a )....
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