# Lecture3 - Energy ο¨ Momentum = π± = ππ ο¨...

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Unformatted text preview: Energy ο¨ Momentum = π± = ππ ο¨ Kinetic = ? πΎ = Β½ ππ π€ ο¨ Potential = ? π = πΒ‘? ο¨ Work = π² = Β’Β£ ο¨ Power = π² / π΅ Potential & Kinetic Energy ο¨ π₯ h = π π π‘ + Β½ ππ‘ 2 ο¨ π- π π = π₯π = ππ‘ ο¨ π 2- π π 2 = 2 π π₯ h ο¨ E K = Β½ ππ£ 2 ο¨ E P = π gh ο¨ E K + E P = E Total Work Requires Displacement ο¨ W = Fβ’d ο¨ Applying a force does not mean work has been done ο¨ Energy is defined as the ability to do Work ο¨ Work done by gravity on a falling object is the loss of potential energy ο¨ By correlation then, it is the gain in kinetic energy ο¨ Units of Nm or kg β m 2 /s 2 or J Conversion of Work to Kinetic Energy The throwerβs stretch d is 2m. He throws a 3kg ball horizontally with a final velocity of 3m/s. 1. Calculate the Force applied to the ball. 2. Calculate the work done by the thrower. 3. Calculate the kinetic energy of the ball when released. 4. Calculate the distance the ball travels after 3 seconds. Kinetic Energy exponentially increases with Velocity ο§ E K = Β½ ππ£ 2 ο§ Calculate the kinetic energy requirement for the above car to go from 0 to 10 m/s ο§ Calculate the kinetic energy requirement for the above car to go from 30 to 40 m/s ο§ Would it consume more energy to travel the same distance on the 95 North as U.S. 1? What if there was no traffic on either road (as far fetched as that may be) ο§ If the above speed change occurs over a period of 10 seconds, calculate the amount of Work done and Power used by the car in each case. Equations of Motion and Projectiles ο¨ y - y π = π₯ y = π π π‘ + Β½g π‘ 2 ο¨ π- π π = π₯π = g π‘ ο¨ π 2- π π 2 = 2gy ο¨ y can be substituted for h when determining the height in the upward direction ο¨ When falling and the peak height is used as the starting point, the height will be: h max β y ο¨ If 1=10m, 2=30m, 3=60m, 4=70m, 5=75m in the above picture, representing the horizontal displacement of a 5kg mass from the faΓ§ade of the 25m tall building, determine (at positions 1-5) the: ο€ 2-D velocity ο€ Potential Energy ο€ Kinetic energy ο€ The work done by gravity Harmonic Oscillators ο¨ In the absence of air resistance (vacuum) and friction, oscillators will perform an indefinitely repeating motion without energy loss...
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## This note was uploaded on 12/04/2011 for the course PHYSICS 1025 taught by Professor Ramos during the Summer '11 term at Miami Dade College, Miami.

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Lecture3 - Energy ο¨ Momentum = π± = ππ ο¨...

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