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Unformatted text preview: 2. WW = 0 Ww = 31 ww = 251 n = 282 cats (can choose to calculate p directly (frequency of W allele), or calculate q first) p = 31/(2 * 282) ≈ 0.055 OR q = (31 + (2 * 251))/(2 * 282) ≈ 0.945 p = 1 – q = 1 – 0.945 = 0.055 3. Males: OY = 26 oY = 78 n = 104 Females: OO = 13 Oo = 49 oo = 93 n = 155 Step 1: Calculate population allele frequencies q pop = (q male + 2(q female ))/3 q male = 78/104 = 0.75 q female = (49 + (2 * 93))/(2 * 155) ≈ 0.758 q pop = (0.75 + (2 * 0.758))/3 ≈ 0.755 p pop = 1 – 0.755 = 0.245 Step 2: Calculate HW genotype frequencies OY = ½ * p pop = 0.245 * 0.5 = 0.1225 oY = ½ * q pop = 0.755 * 0.5 = 0.3775 OO = ½ * p pop 2 = (0.245)2 * 0.5 = 0.03 Oo = ½ * 2p pop q pop = 2 * 0.245 * 0.755 * 0.5 = 0.185 oo = ½ * q pop 2 = (0.755) 2 * 0.5 = 0.285 • Check: add all genotype frequencies to verify they sum to 1...
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This note was uploaded on 12/02/2011 for the course PCB 3063 taught by Professor Marta during the Fall '08 term at University of Florida.
 Fall '08
 MARTA
 Zygote

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