Exam 3 Quy - Version 100 Exam 3 quy(50970 This print-out...

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Version 100 – Exam 3 – quy – (50970) 1 This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. Be SURE to completely bubble in your scantron form. Your score may be penalized for incompletely filling in the name, UTEID, or version number spaces of the form. 001 10.0points A sample of N 2 gas occupies a volume of 746 mL at STP. What volume would N 2 gas occupy at 155 C at a pressure of 368 torr? 1. 2415 mL correct 2. 566 mL 3. 588 mL 4. 312 mL 5. 3295 mL 6. 323 mL 7. 983 mL 8. 1792 mL Explanation: V 1 = 746 mL T 1 = 273 . 15 K P 1 = 1atm = 760torr T 2 = 155 C = 428 K P 2 = 368torr Combined Gas Law: P 1 V 1 T 1 = P 2 V 2 T 2 V 2 = P 1 V 1 T 2 T 1 P 2 = (760torr)(746mL)(428 . 15K) (273 . 15 K)(368torr) = 2414 . 9mL 002 10.0points A sample of water vapor is allowed to reach equilibrium in a closed container at 127 C. The equilibrium pressure is measured as 8 . 2 atm. What is the molar concentration parenleftbigg mol L parenrightbigg of the water vapor? 1. 0 . 80 mol · L 1 2. not enough information is given 3. 0 . 25 mol · L 1 correct 4. 1 . 16 mol · L 1 Explanation: T = 127 C = 400 K mol L = n V = P RT = 8 . 2 atm 0 . 0821 L · atm · mol 1 · K 1 · 400 K = 0 . 25 mol · L 1 003 10.0points A mixture of gases at 25 C and 1 atm. pres- sure contains 10.0 L of oxygen gas, 20.0 L of nitrogen gas, 30.0 L of cabon dioxide, and 15.0 L of hydrogen gas. The percent (by volume) of oxygen gas is 1. 7.5% 2. 40.0% 3. 13.3% correct 4. 10.0% 5. 75.0% Explanation: Percent = Part Whole × 100% Part = 10 L Whole = 10 L + 20 L + 30 L + 15 L = 75 L Percent = 10 L 75 L × 100% = 13 . 3333%
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Version 100 – Exam 3 – quy – (50970) 2 004 10.0points What is the molar mass of a compound that takes 1 . 9 times as long to effuse through a porous plug as it did for the same amount of XeF 2 at the same temperature and pressure? 1. 433.408 2. 308.549 3. 1280.33 4. 643.763 5. 611.173 6. 819.412 7. 380.925 8. 677.2 9. 1100.87 10. 857.081 Correct answer: 611 . 173 g / mol. Explanation: Let Eff 2 be the effusion rate of the com- pound and Eff 1 be the rate of the XeF 2 : Eff 1 = 1 . 9 Eff 2 MW 1 = 169 . 3 g / mol By Graham’s law of effusion, Eff 1 MW , so Eff 1 Eff 2 = radicalbigg MW 2 MW 1 MW 2 = MW 1 parenleftbigg Eff 1 Eff 2 parenrightbigg 2 = 169 . 3 g / mol parenleftbigg 1 . 9 Eff 2 Eff 2 parenrightbigg 2 = 611 . 173 g / mol . 005 10.0points What volume will 20.0 L of He at 50.00 C and 1201 torr occupy at STP? 1. 20.0 L 2. 12.8 L 3. 31.1 L 4. 26.7 L correct 5. 18.6 L Explanation: P 1 = 1201 torr P 2 = 760 torr V 1 = 20 L T 2 = 273.15 K T 1 = 50 + 273.15 = 323.15 K Using the Combined Gas Law, P 1 V 1 T 1 = P 2 V 2 T 2 and recalling that STP implies standard tem- perature (273.15 K) and pressure (1 atm or 760 torr), we have V 2 = P 1 V 1 T 2 T 1 P 2 = (1201 torr) (20 . 0 L) (273 . 15 K) (323 . 15 K) (760 torr) = 26 . 7151 L 006 10.0points Which of the following is diamagnetic? 1. O 2 2 correct 2. O + 2 3. O 2 4. O 2 Explanation: All but O 2 2 are paramagentic (possess un- paired electrons). 007 10.0points The graph shows the Maxwell distribution plots for a given gas at three different temper- atures.
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Version 100 – Exam 3 – quy – (50970) 3 0 500 1000 1500 2000 velocity (m/s) relative number of molecules A B C Which plot corresponds to the highest tem- perature?
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