Homework - Question 1 - A Yes, its a proper probability...

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Unformatted text preview: Question 1 - A Yes, its a proper probability density function. If f(x) = 1, we can say that its a proper probability density function. Question 1 - B Mean E(x) = x.f(x) = 10 *0.02 + 12*0.7 + 14*0.05 + 16*0.2 + 18*0.03 = 13.04 E(x 2 ) = x 2 .f(x) = 10 2 *0.02 + 12 2 *0.7 + 14 2 *0.05 + 16 2 *0.2 + 18 2 *0.03 = 173.52 Variance = E(X 2 ) (E(X) ) 2 = 173.52 13.04 2 = 3.4784 Standard deviation = sqrt(variance) = 1.065 Question 1 - C P( X < 16) = 1 P( X 16) = 1 (0.2 + 0.03) = 0.77 Question 4 - A Solution: Given =1 and 2 = 4 P(Y 3) = P( Z (3 1)/ 2) = P( Z 1) = 0.3413 Question 4 - B Given =3 and 2 = 9 P(Y > 0) = P( Z > (0 3)/ 3) = 1 - P( Z 1) =1 - 0.3413 = 0.6587 Question 5 - A Population mean = 3 inches Variance 2 = 0.57 2 * 22 = 7.1478 Question 5 - B Solution: P(Y 4.3) = P( Z (4.3 3) / Sqrt(7.1478)) = P( Z 0.486) = 1 P(Z < 0.486) = 1 0.1879 = 0.8121 Question 5 - C +--- n t...
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This note was uploaded on 12/04/2011 for the course ECONOMICS 201 taught by Professor Rcollier during the Spring '10 term at Portland CC.

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Homework - Question 1 - A Yes, its a proper probability...

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