Exam1Answer(Bio325) - 2 1. You have fhree dice: one red...

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Unformatted text preview: 2 1. You have fhree dice: one red (R), one green (6), and one blue (8). When all ’rhree dice are rolled al‘ fhe same ’rime, caICulafe the probability of the Following oul'comes l Au). mamas) flex—é; — ‘53 _ l 13(1). 6(R)5(G)6(B) 7‘77: x3; - ——5 l I __ | cu). 6(R)6(G)4(B) ing—é—j r 275 3 D(3). no sixes of all 5 6 i :(2 (0)7be (95 r i i _ 3 E(Z)- Zsixesanleiveonanydice 3(EXQXC0) 0—3 (052 (o 2% ‘ i 9» F (2). 3 sixes or 3 Fives : E Q _ l G (3). fhe same number on all 3 dice (a ((03 > : Z? " E: r a different number on each ‘of Jrhe 3 dice l x5. EL : £0 :19 i (0 (0 3o [8 q H (3). 3 2. Mendel's crosses dealt with alternate alleles oF one or two genes, but the same principles hold For crosses concerning more than two genes. Consider the Following cross, where all oF the alleles interact the way that Mendel’s did, and all alleles assort independently: AaBchDdEe X aaBbchdee A. What proportion of the progeny will phenotypicaliy resemble the parent on the left? (5) AflBfl E__ WW 2 flu: q C? 9 .l :2. ‘— — ;__ : a X X x 1, (QBXLIJ— 2%7—1? B. What proportion oF the progeny will phenotypically resemble the parent on the right? (5) m B CC D_ae, C. What proportion of the progeny will phenotypically resemble either parent? (5) q + q ._—-- ?xiép 23*le [3? D. What proportion of the progeny will phenotypically resemble neither arent? (5) V /'d#_# ll IT: OR l \, a I00 ll (“k 3. The recessive allele c causes people to be albinos (no skin pigmentation at all). People with at least one C allele have normal skin color. IF a C/c man and a c/c woman have 10 children, what is the probability that all oF the children have normal skin color? (6) CL K c {L l \l/ “To . C la; .1 m C of: Z momma,J a mu 4. A rare autosomal recessive allele that is 100% penetrant and inherited in a Mendelian manner causes the disease cystic Fibrosis. A phenotypically normal man whose Father had cystic Fibrosis marries a phenotypically normal woman From outside the Family, and the couple consider having a child. 3 A. Draw the pedigree diagram as For as described 96 CC CC-asfillso 5°“? 9 7 C a /> IL ‘EE'E (cg—’2, B. IF the Frequency in the population oF heterozygotes For cystic Fibrosis is 1 in 50, what is the chance that the couple's First child will have cystic Fibrosis? /O a Pam is Cc because he‘s not armed , .C/icmce +hq+ Mother gch ,5 1/50 , i 2 1 'Clmnre Wt dfli/d cts “c‘ ‘from mo+lW§ :‘s 750 ’L L /100 . nCW ‘H/w ‘AC ‘l flam ,6 vwobabzim eri ch: d is w «.2 m i ,5 C. IF the First child does have cystic Fibrosis, what is the pro a ility that the second child will be normal? flm‘ma‘ 5 If, 0'; x r f 4 K yMom and 900’ VFK'A’EF be. (11:, . “r Ola/Mr; C, is i/ . 5. An X—linked dominant allele that is 100% penetrant causes hypophosphatemia in humans. A man with hypophosPhatemia marries a normal woman. What proportion at their sons will have hypophosphatemia? (5) dirtie your gngwer d 4 WW, Wgycéfi’y 6. Tay-Sachs disease is a rare human disease in which toxic substance accumulate in nerve cells. The recessive allele responsible For the disease is inherited in a simple autosomal Mendelian manner. For unknown reasons, the allele is more common in populations of Ashkenazi Jews of eastern Europe. A woman is planning to marry her First cousin, but the couple discovers that their shared grandfather's sister died in infancy of Tay~Sachs disease, A. Draw the relevant parts of the pedigree, and show all genotypes as completely as possible. (10) circle your entire answer «still-“M _._m 4§\‘jQJTCfi£ 7*” mil?“ fiat 1 8. 'Assuming that all people who marry into the Family are homozygous normal, what is the probability that the cousins’ First child will have Tay—Sachs disease? (10) 2 l j. Chili/ire Mat-i shawl {Mafia/lit: I i3! a? v, 0?, T{ Sl'ic’i’rifil orgasms; is it] 05111;“? "liar L94»; »- [M- H like”. V {it 1 Te 3 ads 5' 7f Wilt’wlmg M It, 0% “that both (an in m 7t .L .l is Z )5?” 43% at» r «urnc“w,cha lira £2 in »{f 6 7. A woman owned a Fine purebred white (whiteness is an autosomal recessive phenotype) Female poodle and wanted to mate her to produce a litter of white puppies. She took the dog to a breeder who said that he would mate the Female with a purebred white male. When six puppies were born, they were all black. The woman sued the breeder For mating her poodle with the wrong male. You are called in as an expert witness. A. Is it possible just on the basis of genetic principles (without any special knowledge oF the genes that cont dog color) For two purebred white dogs to have all black progeny? YES \ NO (circle one) (2) B. (13) g If you answered YES, explain why by drawing the cross between the two dogs using symbols that you define and naming the relevant gene interaction. ll L/——‘ IF you answered NO, explain why not by drawing the cross between the two dogs using symbols that you define and naming the relevant gene interaction. c blaffi l' _‘ _..‘7 in, Fifii__.l ‘L'KJ Sir-N "J. (.0 *1. “W0 ones needed in IMF-r3?" 1?}ng ‘ A n.4,, “ .e i ' art-my" (N (32'16'1’3. flay-gave) gm lie A amd E 959 1’7” ~ ,7. MM. / U f 9 F. _ 1,7,-” -J‘2 3439 we ram’WWTLMM is, M r i i : ___d_____fl._—- ," ‘_ P‘ 1 /‘ ‘ M; X ,4 to >44 gm. :-~ ...
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This note was uploaded on 12/04/2011 for the course BIO 325 taught by Professor Saxena during the Fall '08 term at University of Texas at Austin.

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Exam1Answer(Bio325) - 2 1. You have fhree dice: one red...

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