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Unformatted text preview: HOMEWORK ASSIGNMENT 1 PHYS851 Quantum Mechanics I, Fall 2009 1. [10 pts]What is the relationship between (  ) and (  ) ? What is the relationship between the matrix elements of M and the matrix elements of M . Assume that H = H what is ( n  H  m ) in terms of ( m  H  n ) ? (  ) = (  ) . ( m  M  n ) = ( n  M  m ) . ( n  H  m ) = ( n  H  m ) . Also, because H = H , we have ( n  H  m ) = ( n  H  m ) . Putting these together gives ( n  H  m ) = ( m  H  n ) , which is an equivalent definition of Hermiticity This says firstly, the diagonal elements of a hermitian operator must be real in every possible basis, and secondly, the offdiagonal elements come in complexconjugate pairs, such that H nm = H mn . Thus we can tell just by looking at it whether a matrix is Hermitian or not. 2. Use the matrix representation and summation notation to prove that ( AB ) = B A , where A and B are both operators. Use summation notation to expand (  AB  ) in terms of the constituent matrix elements and vector components? step 1: by definition, we have ( A B ) = ( A B ) T step 2: by the standard rules of matrix algebra, we have ( A B ) T mn = ( A B ) nm = k A nk B km = k ( B ) T mk ( A ) T kn = k B mk A kn = ( B A ) mn 3. Consider the discrete orthonormal basis { m )} , m = 1 , 2 , 3 ,... ,M that spans an Mdimensional Hilbert space, H M . (a) Show that the identity operator, I = m  m )( m  , satisfies I 2 = I . I 2 = ( m  m )( m  )( n  n )( n  ) = mn  m )( m  n )( n  = mn  m ) m,n ( n  = m  m )( m  = I (b) Form a new projector, I !3 , by removing the state  3 ) , i.e. I !3 := m negationslash =3  m )( m  . Does I !3 2 = I !3 ? Is I !3 also the identity operator? I 2 !3 = m,n negationslash =3  m )( m  n )( n  = m,n negationslash =3  m ) m,n ( n  = m negationslash =3  m )( m  = I !3 , so yes to first question....
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This note was uploaded on 12/04/2011 for the course PHY 7070 taught by Professor Smith during the Spring '11 term at Wisconsin.
 Spring '11
 Smith
 Physics, Work

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