Extra Problem 3 - Probability Rules - Solution Key

Extra Problem 3 - Probability Rules - Solution Key - 7000 ....

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EMGT 269 – Elements of Problem Solving and Decision Making Question by Instructor: Dr. J. Rene van Dorp EXTRA PROBLEM 3: PROBABILITY CALCULUS 68 . 0 ) ( = A P , 30 . 0 ) | ( = A B P , 02 . 0 ) | ( = A B P 1. Find ) ( A P , ) ( B A P , ) ( B A P 32 . 0 68 . 0 1 ) ( 1 ) ( = - = - = A P A P 2040 . 0 68 . 0 * 30 . 0 ) ( ) | ( ) ( = = = A P A B P B A P 0064 . 0 32 . 0 * 02 . 0 ) ( ) | ( ) ( = = = A P A B P B A P Next, summarize what we know in a probability table.
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EMGT 269 – Elements of Problem Solving and Decision Making Question by Instructor: Dr. J. Rene van Dorp A A B 2040 . 0 ) ( = B A P 0064 . 0 ) ( = B A P ? ) ( = B P B ? ) ( = B A P ? ) ( = B A P ? ) ( = B P 68 . 0 ) ( = A P 32 . 0 ) ( = A P 1 2. Use your results under 1 and complete the following probability table A A B 2040 . 0 ) ( = B A P 0064 . 0 ) ( = B A P 2104 . 0 ) ( = B P B 4760 . 0 ) ( = B A P 3136 . 0 ) ( = B A P 7896 . 0 ) ( = B P 68 . 0 ) ( = A P 32 . 0 ) ( = A P 1
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EMGT 269 – Elements of Problem Solving and Decision Making Question by Instructor: Dr. J. Rene van Dorp 3. Now use the table to find the following: ) | ( A B P , ) | ( A B P , ) | ( B A P , ) | ( B A P , ) | ( B A P , ) | ( B A P . Note: Always normalize using the probability of the conditioning argument.
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Unformatted text preview: 7000 . 68 . 4760 . ) ( ) ( ) | ( = = = A P B A P A B P 98 . 32 . 3136 . ) ( ) ( ) | ( = = = A P B A P A B P EMGT 269 Elements of Problem Solving and Decision Making Question by Instructor: Dr. J. Rene van Dorp 9696 . 2104 . 2040 . ) ( ) ( ) | ( = = = B P B A P B A P 0304 . 2104 . 0064 . ) ( ) ( ) | ( = = = B P B A P B A P 6028 . 7896 . 4760 . ) ( ) ( ) | ( = = = B P B A P B A P 3972 . 7896 . 3136 . ) ( ) ( ) | ( = = = B P B A P B A P...
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Extra Problem 3 - Probability Rules - Solution Key - 7000 ....

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