Copy of chem 124-expt 3-EXCEL calculation Example

Copy of chem - 30.4 30.8 31.0 24.6 26.6 24.6 w/o outliers 28.4 28.8 Standard deviation 3.8 2.6 median 29.9 29.9 Conclusion q =-m c ∆ T = n ∆ H

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Chem 124-09 Name: Computer # 25 Expt. #3: Heat of sublimation roup 1: Olivia and Austi Group 2 Group 3 Group 4 Run 1 Run 2 Run 3 Run 1 Run 2 Run 3 Run 1 Run 2 Run 3 Run 1 Run 2 Run 3 61.14 59.99 63.98 62.54 63.84 61.34 68.98 64.78 58.55 55.55 54.85 55 15.1 15.3 15.3 14.1 16.7 13.3 15 15 15 15.2 15.6 15.5 60 68.8 74.7 62.9 59.2 69.8 64.2 69.3 73.7 51.1 71.1 70.7 19.9 27.5 32.4 26.6 31.6 33.3 28.3 30.5 30.6 14.5 30 33.1 333 341.8 347.7 335.9 332.2 342.8 337.2 342.3 346.7 324.1 344.1 343.7 292.9 300.5 305.4 299.6 304.6 306.3 301.3 303.5 303.6 287.5 303 306.1 29.9 29.8 32.6 29.6 19.4 31.0
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Unformatted text preview: 30.4 30.8 31.0 24.6 26.6 24.6 w/o outliers 28.4 28.8 Standard deviation 3.8 2.6 median: 29.9 29.9 Conclusion: q = -m c ∆ T = n ∆ H where n is the number of mol of CO 2 ; m = mass of water; c = specific capacity of H 2 O = 4.184 J/gK; ∆ T = Tf - Ti; and ∆ H = heat of sublimation of CO 2 m H2O (g) m dry ice (g) T i (C) T f (C) T i (K) T f (K) ∆ H (KJ/mo Average of ∆ H (KJ/mol)...
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This note was uploaded on 12/05/2011 for the course CHEM 124 taught by Professor Hascall during the Fall '08 term at Cal Poly.

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