CourseNotes.3

# CourseNotes.3 - Parts b& c When A and B are connected by the wire the excess charge on the two spheres will equalize leaving both with a charge

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Unformatted text preview: Parts b) & c) When A and B are connected by the wire, the excess charge on the two spheres will equalize, leaving both with a charge of- 3 . 00 nC . The ground is charge neutral, so all of the excess charge on sphere B will dissipate into the ground leaving it with zero charge. Finally, when B and C are connected by the wire they too will equalize leaving both with a charge of +4 . 00 nC . So the final state after the three successive steps is: q A =- 3 . 00 nC , q B = +4 . 00 nC , and q C = +4 . 00 nC . Parts b and c are now just a simple application of Coulomb’s law. F AC = 1 4 π q A q C d 2 = 2 . 70 μN F BC = 1 4 π q B q C d 2 = 3 . 60 μN 3 Chapter 22: Electric Fields 3.1 The Electric Field Recall from our discussion of gravitation, that we could divide both sides of Newton’s law by the mass of the object upon which the force was acting to obtain the gravitational acceleration....
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## This note was uploaded on 12/05/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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