CourseNotes.10 - charge enclosed by the surface is simply...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
charge enclosed by the surface is simply the total charge on the sphere q . Hence, by Gauss’s law, the field outside must be: E = q ± 0 4 πr 2 which is exactly the same field as a point charge centered at the center of the sphere. Inside of the sphere the same symmetry arguments hold, but the total charge enclosed by the sphere will be proportional to the volume of the sphere. q enc = ρV = q 4 3 πR 3 4 3 πr 3 = q r 3 R 3 Plugging this into Gauss’s law gives the electric field inside of a uniformly charged sphere. E = ± q ± 0 4 πR 3 ² r 4.5 Problems Problem 23.8 Figure 6 shows two nonconducting spherical shells fixed in place. Shell 1 has uniform surface charge density +6 . 0 μC m 2 on its outer surface and radius 3 . 0 cm ; shell 2 has uniform surface charge density +4 . 0 μC m 2 on its outer surface and radius 2 . 0 cm ; the shell centers are separated by L = 10 cm . In unit-vector notation, what is the net electric field at x = 2 . 0 cm ?
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/05/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online