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We must be careful here because our limits of integration will change as
r
changes.
d)
V
=

Z
r
∞
q
1
+
q
2
4
π±
0
r
0
2
dr
0
=
q
1
+
q
2
4
π±
0
r
= 6
.
73
×
10
3
V
e)
V
=

Z
R
2
∞
q
1
+
q
2
4
π±
0
r
0
2
dr
0
=
q
1
+
q
2
4
π±
0
R
2
= 2
.
74
×
10
4
V
f)
V
=

Z
R
2
∞
q
1
+
q
2
4
π±
0
r
0
2
dr
0

Z
r
R
2
q
1
4
π±
0
r
0
dr
0
=
q
1
+
q
2
4
π±
0
R
2
+
q
1
4
π±
0
r

q
1
4
π±
0
R
2
=
1
4
π±
0
±
q
1
r
+
q
2
R
2
²
= 3
.
47
×
10
4
V
The integration works out very similarly for the other two parts giving:
g)
V
=
1
4
π±
0
±
q
1
r
+
q
2
R
2
²
= 4
.
50
×
10
4
V
h)
V
=
1
4
π±
0
±
q
1
R
1
+
q
2
R
2
²
= 4
.
50
×
10
4
V
i)
V
=
1
4
π±
0
±
q
1
R
1
+
q
2
R
2
²
= 4
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Unformatted text preview: . 50 × 10 4 V Figure 11: The Electric Field as a Function of r (The Vertical Axes is Arbitrarily Scaled). Figure 12: The Potential as a Function of r (The Vertical Axes is Arbitrarily Scaled). 17...
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This note was uploaded on 12/05/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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