Unformatted text preview: We can use this to calculate the work done by the applied field. The problem states that the dipole is initially at rest and that its final position is aligned with the magnetic field. We can therefore use conservation of energy to solve this problem. K f + U f = K i + U i K μB = 0 μB cos θ ⇒ θ = arccos 1 K μB For the second part of the problem, we do not even have to do any calculations. This is analogous to a ball rolling through a valley. The ball will roll down the hill, picking up kinetic energy and then on the other side it will roll back up to the same height as it started at. In our case, the magnetic dipole will return to the same angle that it started at. θ 2 = arccos 1 K μB 10 Chapter 29: Magnetic Fields Due to Currents In the last chapter we discussed how charged particles interact with magnetic fields without men tioning how magnetic fields are created. When we discussed electric fields earlier in the semester, we started with the idea of a charged particle and the field which it produced. We then used thewe started with the idea of a charged particle and the field which it produced....
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This note was uploaded on 12/05/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Conservation Of Energy, Energy, Work

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