Our first goal is to set out finding
d
in terms of
r
and
R
since this will control the interference
upon reflection. Using a little trigonometry we can see that the hypotenuse of the triangle formed
by
r
and
R
in the figure is
h
=
√
R
2

r
2
. Hence,
d
is given by
d
=
R

p
R
2

r
2
⇒
r
=
p
2
dR

d
2
Since the problem tells us that
r/R
1 we can treat the light as if it were all coming straight
into the lens/plate setup and reflecting straight back (i.e. we will neglect the fact that the camera
is a single point). The other approximation that we will make is that since the radius of curvature
of the lens is very small we can neglect any refraction effects and treat the rays as if they were
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 Spring '08
 Any
 Physics, Wavelength, ﬁrst reﬂection oﬀ

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