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CorrectedSolution for Problem 1

# CorrectedSolution for Problem 1 - 2 2 2 2 2 2 2 Similarly...

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Problem 1 Area number denotation is referring to previous solution. Thus, total internal work(pay special attention to the displacement of areas 5,6,7 and 8). 4 ! 2 2 " ! l ! k + 2 ! 2 " ! l ! k + 2 ! " ! 2 l ! k = 6 2 " ! l ! k (1,2,5,6) (3,4) (7,8) which should be equal to external work done by the punch. Note that the cross-sectional area of the punch is 2 ! l Thus, ! "#" 2 " l = 6 2 #" l " k \$ ! = 6 " k = 3 ! yield # 1 2 3 4 5 6 7 8 Area l l l l l l 2 l 2 l Displacement 2 2 ! 2

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Unformatted text preview: 2 ! 2 ! 2 ! 2 2 ! 2 2 ! ! ! Similarly for the problem (b), we have, # 1 2 3 4 5 6 7 8 9 10 Area l l l l l l l l 2 l 2 l Displacement 2 2 ! 2 2 ! 2 ! 2 ! 2 ! 2 ! 2 2 ! 2 2 ! ! ! Thus, total internal work 4 ! 2 2 &amp;quot; ! l ! k + 4 ! 2 &amp;quot; ! l ! k + 2 ! &amp;quot; ! 2 l ! k = 8 2 &amp;quot; ! l ! k (1,2,7,8) (3,4,5,6) (9,10) Thus, ! &amp;quot;#&amp;quot; 2 &amp;quot; 2 &amp;quot; l = 8 2 #&amp;quot; l &amp;quot; k \$ ! = 4 &amp;quot; k = 2 ! yield...
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CorrectedSolution for Problem 1 - 2 2 2 2 2 2 2 Similarly...

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