This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 30,000 lb. If the modulus of the aluminum is E = 10,000,000 psi, determine the true strain of the sample. [4 pts.] Solution: A = 1 in 2 and P = 30,000 lb. Hence Engineering stress s = P/A = 30,000 psi Engineering strain e = s/E = 30,000/10,000,000 = 3/1000 = 0.003 True strain = ln (1 + e) = ln ( 1+0.003) = 0.002996 Or elongation = = Pl/AE = (30,000 x 10)/(1 x 10,000,000) = 0.03 eng strain e = /L = 0.03/10 = 0.003 True strain = ln ( 1+e) = 0.002996...
View
Full
Document
This note was uploaded on 12/03/2011 for the course EMA 3702 taught by Professor Wu during the Fall '11 term at FIU.
 Fall '11
 Wu

Click to edit the document details