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23_Mechanics Homework Mechanics of Materials Solution

# 23_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 1.28 I. 28 Determine the largest load P which may be applied at A when 9= 60 knowing that the average shearing stress in the 10- mm- diameter pin at 8 must not exceed I20 MPa and that the a» erage bearing stress in member AB and In the bracket at 8 must not exceed 90 MPa. SOLUTION Gcomci-h/ -' Twiam’h ABC. is an isosci’es “rwanaJJe wan angles Shown h are {)se Jam A as ‘Ff‘ge boéyP Law a“? Sines applies! +12 P ‘Pome +V~mnjj¢ 120' :- FAB ._ PM so ‘H‘i‘uanqh FME" FAB 5"" 3°° = 0.57735 F Fm sin I?!)0 38 w- F _ Ac. 5 in 30° I? shcarina s+r~ess in Pin «2} B is crr’nca) AP = §d1= £40010): = 73.59xlo" w." Fm: 2M: = (2)(78.S‘iv)0"7Ci20*10°\i = I8.250>'103 N IF bearing} \$+Mss in member A8 a nomad a A is affirm-J A;- to' = (0.0!6)(0.0103-‘ 160 HO" Fm = A561 2 (Icoxr0")(‘io xio‘) = 19.40 xio‘N IF beqn‘na shes: in +I~e bum/ltd" a+ B is err-Had A5: 21: d : ‘(2)Co.om)(o.o:o) -.-. quwo'é yin" FAB -—- A56; :.(24¢>W0'r'._)(°{o 210“) = 21.4.on“ u [LP/9a..) do}: Fm is Hie snmlles‘h 1.2. [VJ-{owes N Then) he», sums Pm“: (o.577553(i+.+ox103> = 8.3!!!03 N 3.33)» an ...
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