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24_Mechanics Homework Mechanics of Materials Solution

# 24_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 1.29 PROBLEM 1.30 1.29 The 6- RN load P is supponed by two wooden members of 75 X 125~ mm uniform rectangular cross section which are joined by the simple glued scarf splice shown. Determine the normal and shearing stresses in the glued splice. SOLUTION p :: 6 x103 N e = 9o°- 70" = 20° A, = (0.075)(o.i2s\ = 7.375 x163 m" _ 3?. 2 _W- 3 6‘ — A0 605 9 - 1375,10,; - 565x10 G= 565' 141790; 4 __ .1: _ ___ (3x105) arm 90" 1" 2A. 5m 29 (13(13'IS'XIO‘3) ’31 = 906 9.134.. 4 = 2067103 1.30 Two wooden members of 75 x 125- mm uniform rectangular cross section are joined by the simple glued scarf splice shown. Knowing that the maximum allowable tensile stress in the glued splice is 500 kPa, determine (a) the largest load P which can be safely supported, (1)) the corresponding shearing stress in the splice. SOLUTION 'L A, = (0.0733(0.12§\r = 9.375 ado—3 1m 6' = :00 x103 m = 53°85‘wio’ ) sin Lio- _ g (2X137S‘r10-3) — 131.36: x10 1’: 181.0 kPa. «- ...
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