{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

24_Mechanics Homework Mechanics of Materials Solution

24_Mechanics Homework Mechanics of Materials Solution -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PROBLEM 1.29 PROBLEM 1.30 1.29 The 6- RN load P is supponed by two wooden members of 75 X 125~ mm uniform rectangular cross section which are joined by the simple glued scarf splice shown. Determine the normal and shearing stresses in the glued splice. SOLUTION p :: 6 x103 N e = 9o°- 70" = 20° A, = (0.075)(o.i2s\ = 7.375 x163 m" _ 3?. 2 _W- 3 6‘ — A0 605 9 - 1375,10,; - 565x10 G= 565' 141790; 4 __ .1: _ ___ (3x105) arm 90" 1" 2A. 5m 29 (13(13'IS'XIO‘3) ’31 = 906 9.134.. 4 = 2067103 1.30 Two wooden members of 75 x 125- mm uniform rectangular cross section are joined by the simple glued scarf splice shown. Knowing that the maximum allowable tensile stress in the glued splice is 500 kPa, determine (a) the largest load P which can be safely supported, (1)) the corresponding shearing stress in the splice. SOLUTION 'L A, = (0.0733(0.12§\r = 9.375 ado—3 1m 6' = :00 x103 m = 53°85‘wio’ ) sin Lio- _ g (2X137S‘r10-3) — 131.36: x10 1’: 181.0 kPa. «- ...
View Full Document

{[ snackBarMessage ]}