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26_Mechanics Homework Mechanics of Materials Solution

# 26_Mechanics Homework Mechanics of Materials Solution - tml...

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Unformatted text preview: tml i l m is I i—i i—i_ if i: m PROBLEM [.33 PROBLEM 1.34 1.33 A centric load P is applied to the granite block shown. Knowing that the resulting maximumvaiue ofthe shearing stress in the block is 2 S ksi, determine (a) the magnitude of P, (b) the orientation of the surface on which the maximum shearing stress occurs, (c) the normal stress exerted on that surface, (d) the maximum value of the normal stress in the block. SOL UTION A0." e: (6)“) 7‘ 36 in: The»: 2.51“: 9'5" For Papane o"? ”(W ’L’W=-|E-| lP|= 2A 2’.“ = (2)(3é)(2.s) M" = [30 tops 4: sin 29 = 28 = 510° 9 =- 45° as = ﬂ L o = i = “’80 = - I 6‘5 As. °°° 45 2A0 (any) 25““ “ _ P «180 _ __ — . 6m“ —- To = 36 .. 6 k5! ‘ 1.34 A 240- kip load P is applied to the granite block shown. Determine the resulting maximum value of (a) the normal stress, (1)) the shearing stress. Specify the orientation of the plane on which each of these maximum values occurs. SOLUTION 0 6 :- (ens) . 35 n.‘ :' 7:1- ‘cosze' : 3%}? «3‘6 r. -6.67 coca 0 (CL) Via-:6 +8W51'Ie s‘i‘r-ess ;-" o 0:]- Q = 90" mm. ecu-«premium stress = 6.67 law 4 a‘l‘ 9= ’3” = ’P # 240 _ i. If...“ ‘53: — (23(363 " 3.33 k5 1 «Jr 69 = 45" l l ...
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